最近在做并发测试，用到了多线程去请求server，发现请求的数据太大时会有不少线程抛出操作超时的异常。通过增加一bool变量判断是否超时，如果超时则继续等待，否则返回结果。代码如下,超时的问题暂时解决，但没有分析这样是否足够合理，目前还在测试中...

 说可以加上如下一段代码，感觉和我下面写的效果应该是一样的。

 //这个在Post的时候，一定要加上，如果服务器返回错误，他还会继续再去请求，不会使用之前的错误数据，做返回数据

  HttpWebRequest .ServicePoint.Expect100Continue = false;

 private long RequestMethod(string strParameters)

        {

            long nRet = 0;

            bool bTimeOut = true;

            while (bTimeOut)

            {

                try

                {

                    System.Text.Encoding GB2312 = System.Text.Encoding.GetEncoding("GB2312");

                    byte[] szByte = GB2312.GetBytes(strParameters);

                    string strUri = @"";

                    HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(strUri);

                    httpWebRequest.ContentType = "application/x-www-form-urlencoded";

                    httpWebRequest.ContentLength = szByte.Length;

                    httpWebRequest.Method = "POST";

                    using (Stream reqStream = httpWebRequest.GetRequestStream())

                    {

                        reqStream.Write(szByte, 0, szByte.Length);

                    }

                    using (WebResponse wr = httpWebRequest.GetResponse())

                    {

                        //在这里对接收到的页面内容进行处理

                        Stream responseStream = wr.GetResponseStream();

                        StreamReader responseReader = new StreamReader(responseStream);

                        string strRet = responseReader.ReadToEnd();

                        nRet = wr.ContentLength;

                    }

                    bTimeOut = false;

                }

                catch (WebException ex)

                {

　　　　　　　HttpStatusCode status = ((HttpWebResponse)ex.Response).StatusCode;

                    if (status == HttpStatusCode.RequestTimeout)

                    {

                        Thread.Sleeps(1000);

                    }

                }

            }

          

            return nRet;

        }